question archive 3) Given a binary search tree in pre-order as {22,19,12,6,21,36,40,39}, draw this BST and determine if this BST is the same as one described in post-order as {6,12,21,19,36,40,39,22}

3) Given a binary search tree in pre-order as {22,19,12,6,21,36,40,39}, draw this BST and determine if this BST is the same as one described in post-order as {6,12,21,19,36,40,39,22}

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3) Given a binary search tree in pre-order as {22,19,12,6,21,36,40,39}, draw this BST and determine if this BST is the same as one described in post-order as {6,12,21,19,36,40,39,22}.

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Given a binary search tree in pre-order as {22,19,12,6,21,36,40,39}, draw this BST and determine if this BST is the same as one described in post-order as {6,12,21,19,36,40,39,22}. 
 

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3)

Pre order : ( Root, left , Right) = $22, 19, 12, 6, 21, 36, 40,397. Past order : (left, Right, Root) 2 96, 12121, 19, 3 6 , 40 , 39, 22} . Dnorder : left , Root, Right 22 In BST ( Binary search Tree) in order always sorts in Now nodes into ascending Order. . . Inorder : 16, 121 19 , 21, 22, 36 , 39, 409 In Preorder, first node would be low node and values less from foot would the Part of left. subtree and values goaker from foot node would be right Subtree. so, resultant, BST is: 36 39 Post order inversal = $6, 121 29, 19, 39, 40 / 36, 22 5 The Past order given in question is Shotforrealme GT Neo2 5G realme

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