question archive (5)6113"? DIVE" 11
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(5)6113"? DIVE" 11.3? MUD5-___ e.-3'.I" DIV5= vii-37 MODS— e. is the eel of'imegere {4, T, 15. 1e} pairwise reietiveiy prime? {4) T. Suppose the]. the LCM of two integers is on end their GED is 2. 11' one of the integers is 3!], what is the value of the other integer'? {12} 3. Let x be the deeimel number 455. e. Converter to base 2. b. Convert x to base 3. e. Convert x to base 145. :1. Convert x to base I5.
a. 37 DIV 5 = 7
b. 37 MOD 5 = 2
c. -37 DIV 5 = -8
d. -37 MOD 5 = 3
e. No, the set is not pairwise relatively prime.
7. The other number is 4
8. a. 45510 = 1110001112
b. 45510 = 7078
c. 45510 = 1C716
d. 45510 = 20356
Step-by-step explanation
DIV gives the quotient while MOD gives the remainder of the division problem.
Thus,
a. 37 DIV 5 = 7 and,
b. 37 MOD 5 = 2
that is,
37/5 = 7
remainder = 37- 35 = 2
c. -37 DIV 5 = -8 and,
d. -37 MOD 5 = 3
that is,
-37 / 5 = -7.4 or -8
remainder = -37-(-40) = +3
Take note that the remainder cannot be negative.
e. If the GCD = 1, the numbers are said to be relatively prime.
pairwise,
4 and 7 = GCD = 1
4 and 15= GCD= 1
4 and 16 = GCD = 4, not 1, so this is not pairwise relatively prime
7 and 15 = GCD = 1
7 and 16 = GCD = 1
15 and 16 = GCD = 1
Therefore the set is not relatively prime.
4(7). given:
LCM = 60
GCD = 2
if a = 30 what is b?
LCM method to obtain the greatest common divisor is given as,
GCD (a, b) = (a × b)/ LCM (a, b),
thus,
2= 30b /60
2=0.5b
solving b
b= 2/0.5
b= 4
Conversion
convert 455 to base 2
When we convert decimal to any base, we divide the decimal by the base until the quotient equals 0 and calculate the remainder. The remainders become the destination base digits.
Let us apply, decimal to base 10 we divide by 2
thus,
455 / 2 = 227 remainder 1
227 / 2 = 113 r 1
113 / 2 = 56 r 1
56 / 2 = 28 r 0
28/ 2 = 14 r 0
14/2 = 7 r 0
7/2 = 3 r 1
3/2 = 1 r 1
1/ 2 = 0 r 1
we stop then read the reaminders upwards,
that is, 1110001112
Therfore, 45510 = 1110001112
convert 455 to base 8
455/8 = 56 remainder 7
56/8 = 7 remainder 0
7/8 = = 0 remainder 7
since the whole number is already 0, we stop dividing and read the remainders upwards.
That is, 7078
Therefore, 45510 = 7078
convert 455 to base 16
455/16 = 28 remainder 7
28/16 = 1 remainder 12
1/ 16= 0 remainder 1
since the whole number is already 0, we stop dividing and read the remainders upwards.
That is, 1C716
Therefore, 45510 = 1C716
recall:
10= A in Hexa
11=B
12= C
13=D
14=E
15=F
convert 455 to base 6
455 /6 = 75 r 5
75/6 = 12 r 3
12/6 = 2 r 0
2/6 = 0 r 2
since the whole number is already 0, we stop dividing and read the remainders upwards.
That is, 20356
Therefore, 45510 = 20356