Find the mass in metric tons per day of at -5 °C that would theoretically made in a refrigerating
plant from water at 15 °C, when the mass flowrate of CO, is 0.7 kg/s. If the specific enthalpy of
evaporation of CO, at the evaporator pressure is 290.7 KJ/kg. The dryness fractions of the CO,
entering and leaving the evaporator are 0.22 and 0.98 respectively.
Use the following constants
(4.187 KJ/kg-K, 334 kJ/kg, 2257 KJ/kg).

The refrigerating plant will produce 32.80853 metric tons per day of ice. Please see below for detailed calculations.

Step-by-step explanation

Solve: Given Initial temperature of water Ti= 1s'c Final temperature of water To = -50 0 Mass flow rate of CO = 0.7 ky/&cc. specific enthalpy of evaposiation of co , hey= 290.7 . X1 = 0. 22 4 72= 0.98 . CPwater = 40 187 KJ | Latent head L= 334 KJ / kg Cpo = 2.093 KJ KJ - KI kg K change in enthalpy of CO:- Entering h, = het x, hfg Exit (2- hy ) = ( x 2 - * , ). higg Ah = (0.98 - 0.22) x 290.7 Ah = 2 20. 932 K J /kg Heat absorption rate : Q = Ah . mco Q = 220. 932 x 0.7 KJ/sec Q = 154. 652 KJ / sec Let m ky of water converts in ice. at -5"c thon!- [ Per day ] m [ qual x 15# + L + CP, X5| = 154. 6 52 x [ 3600*24 ] KJ m [ 4. 187 X15 + 334 + 2.093x5) = 154.652 X 3600*24 KJ m = 32808.53 kg m = 32. 80853 metsuc tones / Day . Hence this systemn can make 32. 60853 metsuc tones of ice per day .