A high bypass turbofan has a bypass ratio of 5:1. If the mass flow rate of air entering the engine is
500Kgs-1, the velocity of the aircraft is 120ms-1, the bypass velocity is 180ms-1, the exhaust velocity is
220ms-1 and the mass flow rate at exit from the core is 200Kgs-1. Calculate the engine thrust.

using the information below, please calculate engine thrust showing all workings

The engine thrust is 59kN.

Step-by-step explanation

- Given: By- Pass Ratio = BPR = 5: 1 = 6 Pants Mass flow rate of ais entering the engine = Mo = 500 kg / 2 velocity of the aircraft = free stream velocity = Vo = 120m/92 By-pass velocity = Fan excit velocity = VF = 180 m /2 Exhaust velocity = Cone eseit velocity = Ve = 220m /2 Mass flow rate at exit from the core . = Me = 200 kg / 8 By- Pass satis of all the ais entering the engine, 5 parts of ais bypasses the engine and we pass I pant passes through the come making a total of 6 Parts of ais entering the engine. . . Mass flow Rate of ain by-passing the engine IMF = BPR x Mo 500 6 = 5x 6 - = 416. 67 kg/2 Engine thrust ( F ) = meve + move - Move = (200 * 220 ) + (416.67 x 180 ) - (500*120) = 5900ON 2 59 KN