question archive Determine whether the following situations would require calculating a permutation or a combination
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Determine whether the following situations would require calculating a permutation or a combination. Then solve each problem: 1. What is the number of permutation of 9 objects taken 3 at a time? 2. The covered walk of a school is to be lined with flags, How many different arrangements are there of the 10 flags if 5 are blue, 3 are red and 2 are white? 3. How many different committees of 5 people can be formed from a pool of 9 people? 4. In a 10-item Mathematics problem-solving test, how many ways can you select 5 problems to solve? 5. In how many ways can a team consisting of 2 boys and 3 girls be formed if there are 6 boys and 10 girls who qualified to be a team? Determine whether the following situations would require calculating a permutation or a combination. Then solve each problem: 1. In how many ways can seven students be arranged in a line? 2. If your school canteen offers pork, beef, chicken, and fish for main dish, chop suey, pinakbet, and laing for vegetables dishes, banana and pineapple for dessert, and tea, juice, and softdrinks for beverage, In how many ways can you choose your meal consisting of Icup of rice, Imain dish, I vegetables dish, I beverage, and I dessert. 3. Rabin has 9 mathematics books and 5 science books. The shelf has space for only 7 books. If the first four positions are to be occupied by mathematics books and the last three by science books, in how many ways can this be done? 4. In how many ways can 4 people be seated around a circular table? 5.A box contains 6 red balls and 4 blue balls. Three balls are drawn at random. In how many ways can the 3 balls be drawn from 10 balls a, if the color is not considered? b. if all three balls are blue?
A.
1. Permutation - Answer: 504
2. Permutation- Answer: 2,520 arrangements
3. Combination - Answer: 126
4. Combination - Answer: 252 ways
5. Combination - Answer: 1800 ways
B.
1. Permutation - Answer: 5040 ways
2. Combination - Answer: 72 ways
3. Permutation - Answer: 181,440 ways
4. Permutation- Answer : 24 ways
5. Combination
A. Answer: 120 ways
B. Answer: 4 ways
Step-by-step explanation
Solution:
A.
1) 9P3= 504 or 9x8x7 = 504
2) 10!/5!3!2! = 2,520
3) 9C5 = 126
4) 10C5 = 252
5) 6C2 x 10C3 = 15x120 = 1800
B.
1) 7! = 7x6x5x4x3x2x1 = 5040
2) 4x3x2x3x1 = 72
3) 9P4 x 5P3 = 3024 x 60 = 181,440
4) 4! = 4x3x2x1 = 24
5) A. 10C3 = 120
B. 4C3 = 4