question archive Let (x(t), y(t), z(t)) be the solution of the system x' = y z, y' = −2xz, z' = −3xy with initial condition (x0, y0, z0) and S = {(x, y, z)|x2 + y2 + z2 < 1} be the unit open ball in R3
Subject:MathPrice: Bought3
Let (x(t), y(t), z(t)) be the solution of the system
x' = y z,
y' = −2xz,
z' = −3xy
with initial condition (x0, y0, z0) and S = {(x, y, z)|x2 + y2 + z2 < 1} be the unit open ball in R3 . Show that there exists an open set U ⊂ S, such that if (x0, y0, z0) ∈ U, then x(t), y(t), z(t) ∈ S for all t > 0.
Hint: construct an appropriate quadratic Lyapunov function V (x, y, z), and define the set as U = {(x, y, z) | V (x, y, z) < r0} for some constant r0 > 0.