question archive For each of the following situations involving single amounts, solve for the unknown
Subject:AccountingPrice:2.84 Bought3
For each of the following situations involving single amounts, solve for the unknown. Assume that interest is compounded annually. (/= Interest rate and n= number of years) FV of $1. PV of $1. EVA of $1. PVA of $1. EVAD of S1 and PVAD of $1 (Use appropriate factor(s) from the tables provided. Round your final answers to nearest whole dollar amount.) 1 i 60% 2 3 Present Value Future Value 5 58.000 $ 21,302 5 72.000 5 11.7185 44 500 641345 115.000 $ 11 354 6 18 10.094 $ 10 5 80% 7
Present Value |
Future value |
i |
n |
|
1 |
$40,888 |
$58,000 |
6.0% |
6 |
2 |
$21,302 |
$72,000 |
7.0% |
18 |
3 |
$11,718 |
$44,500 |
10.0% |
14 |
4 |
$64,134 |
$145,000 |
6.0% |
14 |
5 |
$11,354 |
$19,458 |
8.0% |
7 |
Given,
Interest is compounded annually
Formula that is relevant here is,
Future value = Present value (1 + Interest rate)^Number of years
F.V = P.V (1 + i) ^n
1. Present value, P.V
F.V = $58,000
i = 6%
n = 6
F.V = P.V (1 + i) ^n
58,000 = P.V (1+6/100)^6
58,000 = P.V (1.06)^6
58,000 = P.V (1.4185)
P.V = 58,000/1.4185
P.V = 40888 (approximately)
2. Interest rate, i
F.V = P.V (1 + i) ^n
72000 = 21302 (1+i)^18
72000/21302 = (1+i)^18
3.3800 = (1+i)^18
1+i = 18th root of 3.3800
1+i = 1.07
i = 1.07 -1
i = 0.07 or 7%
3. Number of years, n
F.V = P.V (1 + i) ^n
44,500 = 11718 (1+10/100)^n
44500/11718 = (1.1)^n
3.7976 = 1.1^n
n = 14
4. Interest rate, i
F.V = P.V (1 + i) ^n
145,000 = 64,134 (1+i)^14
145,000/64,134 = (1+i)^14
2.2609 = (1+i)^14
1+i = 14th root of 2.2609
1+i = 1.06
i = 1.06 -1
i = 0.06 or 6%
5. Future Value, F.V
F.V = P.V (1 + i) ^n
F.V = 11,354 (1+8/100)^7
F.V = 11354 (1.08)^7
F.V = 11354 (1.7138)
F.V = 19,458