Suppose in a box there are 4 tickets

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Suppose in a box there are 4 tickets. Each ticket has two numbers on it. Ticket one has the numbers 1 and
2; ticket two has the numbers 1 and 3; ticket three has the numbers 5 and 7; and ticket four has the numbers
4 and 2. Define the following two random variables: X is the first number on the ticket and Y is the second
number on the ticket.
Define a new random variable 2X + 3Y. What is the probability that this new random variable with have a
value of 11?
a. 1/4
b. 0
c. 1/8
d. 1/2