question archive Assuming, for simplicity, a block size of 1 KB, search key values that use 8 bytes each and child-node pointers that use 8 bytes, how many child-node pointers (fan-out) could the B+ tree have at most? Explain
Assuming, for simplicity, a block size of 1 KB, search key values that use 8 bytes each and child-node pointers that use 8 bytes, how many child-node pointers (fan-out) could the B+ tree have at most? Explain
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Assuming, for simplicity, a block size of 1 KB, search key values that use 8 bytes each and child-node pointers that use 8 bytes, how many child-node pointers (fan-out) could the B+ tree have at most? Explain
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Answer:
Block size = 1 KB = 1024 B
Now Key size is 8 bytes and child node pointer is also 8 bytes .
In a B+ tree if a node is internal node then it contains only key and block pointer pairs . Record pointer is only present in leaf node .
Now in an internal node if there are "n" child pointers then there will be "n-1" keys .
So ,
1024 = 8(n) + 8(n-1)
16n - 8 = 1024
16n = 1032
n = 64.5
Here we will take floor value of 64.5
So Number of child node pointers B+ tree have at most is 64 .
