question archive Consider the motion of a 1
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Consider the motion of a 1.00-kg particle that moves with potential energy given by U(x) = -(2.0 J?m)/x + (4.0 J?m2)/x2. Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?
Answer:
it's potential energy at x = 1 and x = 5
U(1) = 2 J
U(5) = -0.24J
therefore change in potential energy = 2.24J
we know that change in potential energy = change in kinetic enrgy
=> 2.24 = 0.5v^2 - 0.5.(3)^2
=> V = 3.67m/s
therefore speed at x = 5m is 3.67m/s