question archive Modify and test the program access_cars
Subject:Computer SciencePrice:2.89 Bought3
Modify and test the program access_cars.php to handle UPDATE and INSERT SQL commands, as well as SELECT.
<?php
$db_hostname = 'localhost';
$db_username = 'root'; //enter your username
$db_password = ''; // enter password else leave it as default
$db_name = 'test'; // enter the name of your database on which you are working
$conn = mysqli_connect($db_hostname, $db_username, $db_password, $db_name);
if(!$conn) {
echo "An error occurred can’t connect to DataBase ".mysqli_error($conn);die;
} else {
echo “connected to DataBase";
}
//----------------------------------Insert--------------------------------------------
mysqli_select_db($conn, $db_name);
$sql = "INSERT INTO cars (id,name, price) VALUES (123432,’Swift’,50000)";
$query = mysqli_query($conn, $sql);
if (!$query) {
echo "Car does not inserted. " . mysqli_error($conn);
} else {
echo "Car inserted successfully.";
}
//-------------------------Update------------------------------------------------
$sql = "UPDATE cars SET name= 'Honda’ WHERE id=123432 ";
$query = mysqli_query($conn,$sql);
if(!$query)
{
echo "Record is not Updated.".mysqli_error($conn);die;
}
else
{
echo "Data successfully updated";
}
//--------------------------------------select------------------------------------
$sql = "SELECT * FROM cars";
$query = mysqli_query($conn,$sql);
if(!$query)
{
echo "Query does not work.".mysqli_error($conn);die;
}
while($data = mysqli_fetch_array($query))
{
echo "id = ".$data['id']."<br>";
echo "car_name = ".$data['name']."<br>";
echo "price = ".$data[‘price’]."<br>";
}
?>