question archive In humans, the allele for six fingers (F) is dominant to the allele for five fingers (f)
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In humans, the allele for six fingers (F) is dominant to the allele for five fingers (f). If both parents are heterozygous for six fingers, what is the probability that their first child will be "normal" (have five fingers)? genotypes phenotypes First, enter the possible genotypes (e.g., FF, Ff, ff) and phenotypes (5 fingers or 6 fingers). What is the cross between two heterozygous parents? Now, put the alleles from one parent on one side, and the alleles from the other parent across the top and fill in the Punnett square. What is the genotype for 5 fingers? Referring to the Punnett square above, what is the probability that the first child will have 5 fingers?
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