question archive Given:g(x):R---->R is continuousg(0)=1 Show that if there exists a +ve no
Given:g(x):R---->R is continuousg(0)=1 Show that if there exists a +ve no
Subject:MathPrice: Bought3
Given:g(x):R---->R is continuousg(0)=1
Show that if there exists a +ve no. 'a' where g is zero..i.e. g(a)=0, then there exists a smallest +ve no. 'k' where g(k)=0.
Hint: Consider the set of all positive x where g(x)=0
Note: This is the complete question,Concepts which may be used: Convergence of sequences and Continuity of a function.
