question archive The formation of one mole of sodium bicarbonate (NaHCO3) from its elements releases 947
The formation of one mole of sodium bicarbonate (NaHCO3) from its elements releases 947
Subject:ChemistryPrice: Bought3
The formation of one mole of sodium bicarbonate (NaHCO3) from its
elements releases 947.7 kJ of thermal energy into the environment. We can represent this change in enthalpy by the equation: A. Na (s) + 0.5 H2 (g) + C (s) +1.5 O2 (g) → NaHCO3 (s) + 947.7 kJ B. Na (s) + 0.5 H2 (g) + C (s) + 1.5 O2 (g) + 947.7 kJ → NaHCO3 (s) C. Na + (aq) + HCO3 - (aq) → NaHCO3 (s) + 947.7 kJ D. Na + (aq) + HCO3 - (aq) + 947.7 kJ → NaHCO3 (s) 7. If we rewrite the equation below for producing one mole of CH4 (g) while expressing energy as part of the equation, then the energy will be Al4C3 (s) + 12 H2 O (l) → 4 Al (OH) 3 (s) + 3 CH4 (g) ? H = -1 763.0 kJ A. 587.7 kJ on the reagent side B. 1763.0 kJ on the reagent side C. 587.7 kJ on the product side D. 1,763.0 kJ on the product side PS. Please, make sure your writing is EASY to read !
