question archive Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year
Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year
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Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year.
What is the 95% confidence interval for this population proportion? Answer choices are rounded to the hundredths place.
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0.11 to 0.21
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0.10 to 0.23
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0.16 to 0.17
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0.11 to 0.16
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Answer:
sample proportion=21/125=0.168
95% confidence interval for this population proportion
=0.168+/-1.96*sqrt(0.168*(1-0.168)/125)
=0.168+/-0.066
=(0.10, 0.23)
