question archive Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year
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Sukie interviewed 125 employees at her company and discovered that 21 of them planned to take an extended vacation next year.
What is the 95% confidence interval for this population proportion? Answer choices are rounded to the hundredths place.
0.11 to 0.21
0.10 to 0.23
0.16 to 0.17
0.11 to 0.16
Answer:
sample proportion=21/125=0.168
95% confidence interval for this population proportion
=0.168+/-1.96*sqrt(0.168*(1-0.168)/125)
=0.168+/-0.066
=(0.10, 0.23)