Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V?) = 3.25 L

Initial temperature (T?) = 292 K

Final volume (V?) = 10 L

Final temperature (T?) =?

V?/T? = V?/T?

3.25 / 292 = 10 / T?

Cross multiply

3.25 × T? = 292 × 10

3.25 × T? = 2920

Divide both side by 3.25

T? = 2920 / 3.25

T? = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

Therefore the final temperature of the gas is 625.46 °C