question archive A certain mutual fund invests in both U

A certain mutual fund invests in both U

Subject:StatisticsPrice: Bought3

A certain mutual fund invests in both U.S. and foreign markets. Let xxμσxxxHint:The random variable be a random variable that represents the monthly percentage return for the fund. Assume  has mean  = 1.9% and standard deviation  = 0.4%.(a) The fund has over 250 stocks that combine together to give the overall monthly percentage return . We can consider the monthly return of the stocks in the fund to be a sample from the population of monthly returns of all world stocks. Then we see that the overall monthly return  for the fund is itself an average return computed using all 250 stocks in the fund. Why would this indicate that  has an approximately normal distribution? Explain.  See the discussion after Theorem 6.2.

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x

 

x-bar

 is a mean of a sample size n = 250. By the 

 

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theory of normality

 

central limit theorem

 

law of large numbers

 , the 

 

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x-bar

 

x

 distribution is approximately normal.

 

(b) After 6 months, what is the probability that the average monthly percentage return x will be between 1% and 2%? Hint: See Theorem 6.1, and assume that x has a normal distribution as based on part (a). (Round your answer to four decimal places.)

 

 

(c) After 2 years, what is the probability that x will be between 1% and 2%? (Round your answer to four decimal places.)

 

 

(d) Compare your answers to parts (b) and (c). Did the probability increase as n (number of months) increased?

Yes

No

    

 

Why would this happen?

The standard deviation 

 

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increases

 

decreases

 

stays the same

 as the 

 

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mean

 

sample size

 

average

 

distribution

 increases.

 

(e) If after 2 years the average monthly percentage return was less than 1%, would that tend to shake your confidence in the statement that μ = 1.9%? Might you suspect that μ has slipped below 1.9%? Explain.

This is very unlikely if μ = 1.9%. One would not suspect that μ has slipped below 1.9%.

This is very likely if μ = 1.9%. One would not suspect that μ has slipped below 1.9%.

    

This is very likely if μ = 1.9%. One would suspect that μ has slipped below 1.9%.

This is very unlikely if μ = 1.9%. One would suspect that μ has slipped below 1.9%

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