question archive What is the molar concentration of a potassium permanganate solution?  Evidence Titration of 10

What is the molar concentration of a potassium permanganate solution?  Evidence Titration of 10

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What is the molar concentration of a potassium permanganate solution?

 Evidence

Titration of 10.0 mL of Acidified 0.100 mol/L FeSO4(aq) with KMnO4(aq)

Trial 1 2 3 4

Final buret reading (mL) 11.3 21.9 32.5 43.1

Initial buret reading (mL) 0.1 11.3 21.9 32.5

Volume of KMno4(aq) added (ml) 11.2 10.2 10.6 10.6

Analysis:

 

10 FeSO4(aq) + 2 KMnO4(aq) + 8 H2SO4(aq) → 5 Fe2(SO4)3(aq) + K2SO4(aq) + 2 MnSO4(aq) + 8H2O(l)

 

Make sure all your answers have the correct number of significant digits and units. 

 

Analysis:

 

1) Find average volume of KMnO4(aq) used.

2) Find the moles of KMnO4(aq). 

3) What is the molar ratio (unknown:known)

4) Find the concentration of the FeSO4(aq) solution. 

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Answer:

a)

volume of KMnO4=10.47mL

b)

Moles of KMnO4=0.0002moles

c)

Molarity of KMnO4=0.0191M

d)

Concentration of FeSO4 solution is already given as 0.1M

Step-by-step explanation

a)

Average volume of KMnO4=10.2+10.6+10.6=10.47mL

We have ignored trial 1 because of the big deviation in volume that will cause less accuracy in our results

Therefore the volume of KMnO4=10.47mL

b)

Moles of FeSO4=volume*molarity=(10/1000)*0.1=0.001moles

Use the mole ratio of FeSO4:KMnO4=10:2=5:1

Moles of KMnO4=(1/5)*0.001=0.0002moles

Moles of KMnO4=0.0002moles

c)

Molarity of KMnO4=moles /volume in liters=0.0002/10.47*10^-3L

Molarity=0.0191M

Molarity of KMnO4=0.0191M

d)

Concentration of FeSO4 solution is already given as 0.1M