question archive What is the molar concentration of a potassium permanganate solution? Evidence Titration of 10
What is the molar concentration of a potassium permanganate solution? Evidence Titration of 10
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What is the molar concentration of a potassium permanganate solution?
Evidence
Titration of 10.0 mL of Acidified 0.100 mol/L FeSO4(aq) with KMnO4(aq)
Trial 1 2 3 4
Final buret reading (mL) 11.3 21.9 32.5 43.1
Initial buret reading (mL) 0.1 11.3 21.9 32.5
Volume of KMno4(aq) added (ml) 11.2 10.2 10.6 10.6
Analysis:
10 FeSO4(aq) + 2 KMnO4(aq) + 8 H2SO4(aq) → 5 Fe2(SO4)3(aq) + K2SO4(aq) + 2 MnSO4(aq) + 8H2O(l)
Make sure all your answers have the correct number of significant digits and units.
Analysis:
1) Find average volume of KMnO4(aq) used.
2) Find the moles of KMnO4(aq).
3) What is the molar ratio (unknown:known)
4) Find the concentration of the FeSO4(aq) solution.
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Answer:
a)
volume of KMnO4=10.47mL
b)
Moles of KMnO4=0.0002moles
c)
Molarity of KMnO4=0.0191M
d)
Concentration of FeSO4 solution is already given as 0.1M
Step-by-step explanation
a)
Average volume of KMnO4=10.2+10.6+10.6=10.47mL
We have ignored trial 1 because of the big deviation in volume that will cause less accuracy in our results
Therefore the volume of KMnO4=10.47mL
b)
Moles of FeSO4=volume*molarity=(10/1000)*0.1=0.001moles
Use the mole ratio of FeSO4:KMnO4=10:2=5:1
Moles of KMnO4=(1/5)*0.001=0.0002moles
Moles of KMnO4=0.0002moles
c)
Molarity of KMnO4=moles /volume in liters=0.0002/10.47*10^-3L
Molarity=0.0191M
Molarity of KMnO4=0.0191M
d)
Concentration of FeSO4 solution is already given as 0.1M
