question archive To facilitate calculations here molar masses of involved elements to be used: Aluminum 26
To facilitate calculations here molar masses of involved elements to be used: Aluminum 26
Subject:ChemistryPrice: Bought3
To facilitate calculations here molar masses of involved elements to be used: Aluminum 26.982 Arsenic 74.922 Barium 137.327 Bromine 79.904 g/mol g/mol g/mol g/mol Calcium 40.078 Carbon 12.011 Chlorine 35.453 Hydrogen 1.008 g/mol g/mol g/mol g/mol Iron 55.845 Lead 207.2 g/mol g/mol Lithium 6.941 g/mo Magnesium 24.305 g/mol Manganese 54.938 Molybdenum Nitrogen 14.007 Oxygen 15.999 g/mol 95.962g/mol g/mol g/mol Phosphorous 30.974 Potassium 39.098 Selenium 78.960 Sodium 22.990 g/mol g/mol g/mol g/mol Strontium 87.62 Sulphur 32.061 Tellurium 127.60 Vanadium 50.942 g/mol g/mol g/mol g/mol 25.67 mL of 4.786 Miron (III) chloride solution reacted with 26.57 mL of 5.376 M ammonium carbonate producing iron (III) carbonate as precipitate at 89.58%. Solve following questions using ICE tables (other methods will not be accepted). 1. (3) Write a balanced chemical reaction with states of matter for compounds. 2. (7) Determine the limiting reagent, theoretical mass and actual mass of precipitate. 3. (20) Determine the molarity of all ions in solution.
