question archive A certain metal M forms a soluble nitrate salt MNO3
A certain metal M forms a soluble nitrate salt MNO3
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A certain metal M forms a soluble nitrate salt MNO3. Suppose the left half cell of a galvanic cell apparatus is filled with a 2.50 mM solution of MNO3 and the right half cell with a 5.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 35.0 °C.
Which electrode will be positive?
Left
Right
What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode.
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
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Answer:
This is known as a concentration, in a concentration cell, the compartment with the more dilute concentration is the anode while the compartment with the more concentrated solution is the cathode. Since the left compartment is more dilute (2.50mM), then it is the anode (negative electrode). Since the right compartment is more concentrated (5.00M), then it is the cathode (positive electrode).
Answer: right half cell
?E=Eocell−RT?/nF ln ?[M+]anode/[M+]cathode???
Eocell for concentration cells is equal to zero since both the Eored and Eoox are of the same magnitude but opposite in sign.
?E=0V−(8.314 J/molK?)(35+273.15)K/(1)(96485 C/mol?) IN 2.50x10−3M?/5M?
Answer: E=0.20V
