question archive The magnetic field inside a solenoid of circular cross section is given by B? =btk^, where b = 2
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The magnetic field inside a solenoid of circular cross section is given by B? =btk^, where b = 2.1 T/ms . At time t = 0.50 ?s , a proton is inside the solenoid at x = 4.8 cm , y= z=0 , and is moving with velocity v? = 5.0 j^Mm/s . The center of the solenoid is at x = y = 0.
Find the electromagnetic force on the proton.
Fx, Fy, Fz = ? N
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