question archive You have been given the task of finding out what proportion of students that enroll in a local university actually complete their degree

You have been given the task of finding out what proportion of students that enroll in a local university actually complete their degree

Subject:StatisticsPrice:2.84 Bought7

You have been given the task of finding out what proportion of students that enroll in a local university actually complete their degree. You have access to first year enrolment records and you decide to randomly sample 120 of those records. You find that 82 of those sampled went on to complete their degree.

a)Calculate the proportion of sampled students that complete their degree. Give your answer as a decimal to 2 decimal places.

Sample proportion = 

You decide to construct a 95% confidence interval for the proportion of all enrolling students at the university that complete their degree. You may find this standard normal table useful for the following questions. If you use your answer to part a) in the following calculations, use the rounded version.

b)Calculate the lower bound for the confidence interval. Give your answer as a decimal to 3 decimal places.

Lower bound for confidence interval = 

c)Calculate the upper bound for the confidence interval. Give your answer as a decimal to 3 decimal places.

Upper bound for confidence interval = 

pur-new-sol

Purchase A New Answer

Custom new solution created by our subject matter experts

GET A QUOTE

Answer Preview

(a) Sample proportion = 0.68

(b) Lower bound for confidence interval = 0.597

(c) Upper bound for confidence interval = 0.763

Step-by-step explanation

(a)

Proportion of sampled students that complete their degree:

Sample proportion, ?p^?? = Number of students that complete their degree / Total sampled students = 82/120 = 0.683 ?≈? 0.68

 

Confidence interval for proportion is given by

?(p^?−zc?np^?(1−p^?)??, p^?+zc?np^?(1−p^?)??)? where

?zc?=1.96? for 95% confidence interval.

Hence, 95% confidence interval is

?(0.68−1.961200.68(1−0.68)??, 0.68+1.961200.68(1−0.68)??)?

?=(0.597, 0.763)?

 

(b)

Lower bound for confidence interval = 0.597

 

(c)

Upper bound for confidence interval = 0.763

 

?P.S. Let me know in the comments if you have any doubt.?