question archive Resultant Vector of Typhoon YolandaVector x-component y-component425 km E SE Identify the velocity of Typhoon Yolanda as it enters and exit the Philippine Area of Responsibility

Resultant Vector of Typhoon YolandaVector x-component y-component425 km E SE Identify the velocity of Typhoon Yolanda as it enters and exit the Philippine Area of Responsibility

Subject:PhysicsPrice:4.99 Bought6

Resultant Vector of Typhoon YolandaVector x-component y-component425 km E SE Identify the velocity of Typhoon Yolanda as it enters and exit the Philippine Area of Responsibility. Calculate the resultant velocity.

Velocity (m/s)

64 km/h W

241 km/h W

34 km/h W

250 km/h W

314 km/h W

78 km/h W

314 km/h W

298 km/h W

 

Summation of x = _____________

Summation of y = _____________

Thetha = ____________

Vx = ____________           

Vy = ___________________

V = ___________

 

pur-new-sol

Purchase A New Answer

Custom new solution created by our subject matter experts

GET A QUOTE

Answer Preview

The given velocities are:

v1 = 425 km/h SE

v2 = 64 km/h W

v3 = 241 km/h W

v4 = 34 km/h W

v5 = 250 km/h W

v6 = 314 km/h W

v7 = 78 km/h W

v8 = 314 km/h W

v9 = 298 km/h W

 

Here

V = v2 + v3 + ....+ v9

V = 64+241+34+250+314+78+314+298

V = 1593km/h

 

Vector component along X axis (East):

Vx = v1cos45° - V

Vx = 425cos45° - 1593

Vx = -1292.480 km/h

or

Vx = 1292.480 km/h (along West)

 

Vector component along Y axis (North):

Vy = -v1sin45°

Vy = -425sin45°

Vy = -300.520 km/h

or

Vy = 300.520 km/h (along the South)

 

theta = tan-1(Vy/Vx)

theta = tan-1(300.52/1292.48)

theta = 13.089° South of West (with -X axis)

or

theta = (180+ 13.089)° with X axis

theta = 193.089° with X axis

 

V = √{Vx2 + Vy2}

V = √{1292.482 + 300.522}

V = 1326.96 km/h