question archive The total electric flux from a cubical box 28
The total electric flux from a cubical box 28
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The total electric flux from a cubical box 28.0 cm on a side is 1.65*103 Nm2/C. What charge is enclosed by the box?
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Answer:
By Gauss' Law:
flux= phi= E?A = q/?o
q/?o= 1.65*103 Nm2/C then q=1.65*103 Nm2 * 8.85*10^-12 C^2/N-m^2
q=1.46*10^-8C
= 14.61 nC
