question archive A worker accidentally added 3kg of CdCl2 into an 80,000 L pond, The water in the pond had a pH of 6
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A worker accidentally added 3kg of CdCl2 into an 80,000 L pond, The water in the pond had a pH of 6.9 and a total carbonate concentration of 2x10^-3 M. Does any precipitate form? If so which one? How much was formed? what is the remaining total soluble cadmium concentration in the pond? Assume no interactions with the atmosphere?
Consider the possible formation of the following solids:
Cd(OH)2(s) = Cd2+ + 2OH- Ks0= 10^-14.35
CdCO3(s) = Cd2+ + CO3 2- Ks0 = 10^-12.1
Consider hydroxide and carbonate complexes