question archive A 500-g particle is located at the point r = 4m i^+ 3m j^- 2m k^ and is moving with a velocity v 3) = 5 m/s i^ -2 ms j^+ 4 m/s k^
A 500-g particle is located at the point r = 4m i^+ 3m j^- 2m k^ and is moving with a velocity v 3) = 5 m/s i^ -2 ms j^+ 4 m/s k^
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A 500-g particle is located at the point r = 4m i^+ 3m j^- 2m k^ and is moving with a velocity v 3) = 5 m/s i^ -2 ms j^+ 4 m/s k^. What is the angular momentum of this particle about the origin?
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Answer:
L= rX P= rXmv= m[ rXV]
we get rX V = 8i-26j-23k
L= m[rX V ]= 0.5kg *[ 8i-26j-23k]= [4i-13j-11.5 k] kgm2/s
