question archive A sample of 8
A sample of 8
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A sample of 8.51 g of solid calcium hydroxide is added to 26.5 mL of 0.340 M aqueous hydrochloric acid.
Enter the balanced chemical equation for the reaction, Physical states are optional and not graded.
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What is the limiting reactant?
Calcium hydroxide
Hydrochloric acid
How many games of salt are formed after the reaction is complete?
Number_______
Hoe many grams of the axcess reactant remain after the reaction is complete?
Number_______
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Answer:
a)
Ca(OH)2 + HCl(aq) = H2O(l) + CaCl2(aq)
balance
Ca(OH)2 + 2HCl(aq) = H2O(l) + CaCl2(aq)
b)
mmol of Ca(OH)2 = mass/MW = 8.51/74.0927 = 0.1148 mol of Ca(OH)2
mol of HCl = MV = (0.34)(26.5*10^-3) = 0.00901 mol of HCl
clearly, there is excess base, so
HCl is limiting
c)
mass of salt formed --> 0.00901 mol of HCl --> 0.00901*1/2
0.004505 mol of CaCl2 forms
mass = mol*MW = 0.004505*110.98 = 0.4999 = 0.50 g of CaCl2
d)
excess left -->
mol of Ca(OH)2 =0.1148 - 0.00901 = 0.10579 mol of base left
mass = mol*MW = 0.10579*74.1 = 7.839 g of Ca(OH)2 left
