question archive An h=2 m tall professor of mass m=80 kg is moving at 0=1 m/s towards a chain which catches his foot, exactly at ground level
An h=2 m tall professor of mass m=80 kg is moving at 0=1 m/s towards a chain which catches his foot, exactly at ground level
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An h=2 m tall professor of mass m=80 kg is moving at 0=1 m/s towards a chain which catches his foot, exactly at ground level. Treat the professor as a uniform rigid rod.
Just prior to touching the chain, the professor's angular momentum is given by velocity times mass times the vertical distance from center of mass to chain. Angular momentum is conserved in collision with the chain. (Why?)
Which of the following gives the professor's angular velocity right after his foot is caught on the chain?
A. Wf = vi/h
B. Wf = 3/2 vi/h
C. Wf = 2/3 vi/h
D. Wf = 6 vi/h
E. Wf = 3 vi/h
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Answer:
Angular momentum is conserved because there is no net torque acting om the system.
A. Wf = vi/h
Step-by-step explanation
By angular momentum consrrvation, if net torque acting on the system is zero, the the angular momentum of the system will be constant.
Angular velocity is given by the ratio of velocity and the radius.
So, if v is the velocity of person, and h is the radius, then the angular speed will be:
Wf = v/h
So, the correct optiin is:
A. Wf = vi/h
