question archive Suppose a brand of light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr
Suppose a brand of light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr
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Suppose a brand of light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr. Find the probability that a light bulb of that brand lasts between 1120 hr and 1495 hr.
Areas Under the Standard Normal Curve z A 1.00 .3413 1.50 .4332 1.10 .3643 1.60 .4452 1.20 .3849 1.70 .4554 1.30 .4032 1.80 .4641 1.40 .4192 1.90 .4713
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Solution:- Given that information : mean = 1300 standard deviation = 150
Z = (X - μ)/σ
=> P(1120 < X 1495) = P( (1120 - 1300)/150 < Z < (1495-1300)/150 )
= P(-1.2 < Z < 1.3)
= 0.9032 - 0.1151
= 0.7881
