a) The physical address of 8086-microprocessor is "20-bit" wide to access the "1MB" memory. However, its registers and memory location are "16bit" wide so how can it access the "20bit" physical address of memory, Justify it: (05 Marks). b) Write down the associations of "Pointer" and "Index" registers with respect to memory segments, also justify the associations of these registers with memory segments in terms of calculation of any physical address of any selected segment: (05 Marks).

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