question archive Complete the following table, assuming the volumes are additive
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Complete the following table, assuming the volumes are additive.
Test Tube |
0.25 m CuSO4 (mL) |
Distilled Water (mL) |
Total Volume with Water (mL) |
Concentration (mol/L) |
1 |
10 |
0 |
10 |
|
2 |
8 |
2 |
10 |
|
3 |
6 |
4 |
10 |
|
4 |
4 |
6 |
10 |
|
5 |
2 |
8 |
10 |
|
Test Tube 1: 0.25 mol/L
Test Tube 2: 0.20 mol/L
Test Tube 3: 0.15 mol/L
Test Tube 4: 0.10 mol/L
Test Tube 5: 0.050 mol/L
Step-by-step explanation
The first test tube consists of only the 0.25 M CuSO4 solution and no distilled water so its concentration must be 0.25 M. The following test tubes are then diluted versions where CuSO4 makes up, respectively, 80%, 60%, 40%, and 20%, of the 10 mL solution. The concentrations of these solutions will then be, respectively, 80%, 60%, 40%, and 20% of the concentration of test tube 1.