question archive A person pushes a 22
A person pushes a 22
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A person pushes a 22.9-kg shopping cart at a constant velocity for a distance of 18.6 m on a flat horizontal surface. She pushes in a direction 27.4 ° below the horizontal. A 35.5-N frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts? Determine the work done by (b) the pushing force, (c) the frictional force, and (d) the gravitational force
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Answer:
Let that force = F
constant velocity so accleration will be zero
horizontal force = F*cos(27.4)
apply Fnet =ma but a= 0 so Fnet
Fnet = 35.5- F*cos(27.4) = 0
F= 35.5 / cos(27.4) = 39.9857 N
a) 39.9857 N
b)
workdone by pushing force = F*d*cos(27.4) = 39.9857 *cos(27.4) * 18.6 = + 660.3 J
C)
Wfriction = -35.5 * 18.6 = -660.3 J
D)
0 because gravitational force is perpendiculer to displacement
