What is the mass of 35g of CuSo4 . 5H20

 

The formula mass or molar mass of CuSO₄.5H₂O is the total sum of the formula masses of its components multiplied by the number of atoms present in each component in the compound. Thus:

Formula Mass of compound = ?Σ?(number of atoms of elements in the compound)*(atomic mass of element)

And, the compound CuSO₄.5H₂O contains 1 atom of Cu, 1 atom of S, 4 atoms of O, and 5 atoms of H₂O (10 atoms H and 5 atoms O).

Formula Mass of CuSO₄.5H₂O = (1 atom Cu)(Formula Mass of Cu) + (1 atom S)(Formula Mass of S) + (4 atoms O)(Formula Mass of O) + (5 atoms H₂O)

--->(We will break down H₂O into H and O for a more accurate calculation of the formula mass of CuSO₄.5H₂O)

--->(For each formula mass of the element, refer to the periodic table of elements. In the periodic table of elements, the formula mass of each element would be labelled as its "atomic mass". The atomic mass and formula mass have the same value but different units. The atomic mass may have units in amu and the formula mass in ?molg??. So, just change the units from amu to ?molg?? when you are calculating.)

Formula Mass of CuSO₄.5H₂O = (1 atom Cu)(Formula Mass of Cu) + (1 atom S)(Formula Mass of S) + (4 atoms O)(Formula Mass of O) + (10 atoms H)(Formula Mass of H) + (5 atoms O)(Formula Mass of O)

Formula Mass of CuSO₄.5H₂O = (1)(63.546?molg??) + (1)(32.065?molg??) + (4)(15.999?molg??) + (10)(1.00784?molg??) + (5)(15.999?molg??)

Formula Mass of CuSO₄.5H₂O = 63.546?molg?? + 32.065?molg?? + 63.996?molg?? + 10.0784?molg?? + 79.995?molg??

Formula Mass of CuSO₄.5H₂O = 249.6804?molg??

The answers to your questions are:

1.)

I believe this would be the moles of 35 g of CuSO₄.5H₂O. Thus:

moles of CuSO₄.5H₂O = given amount of CuSO₄.5H₂O in grams * (?formulamassofCuSO4?.5H2?O1??)

moles of CuSO₄.5H₂O = 35 g of CuSO₄.5H₂O * (?249.6804molg?1??)

--->(we divide the given amount with the formula mass so that the g units will be cancelled and we will be left with the moles unit)

moles of CuSO₄.5H₂O = 0.14 moles

2.) Follow-up question:

grams of CuSO₄.5H₂O = given amount of CuSO₄.5H₂O in moles * (Formula Mass of CuSO₄.5H₂O)

grams of CuSO₄.5H₂O = 3.2 moles CuSO₄.5H₂O * (249.6804?molg??)

--->(we multiply the given amount with the formula mass so that the moles units will be cancelled and we will be left with the g unit)

grams of CuSO₄.5H₂O = 798.97728 g CuSO₄.5H₂O

grams of CuSO₄.5H₂O = 798.98 g CuSO₄.5H₂O

FINAL ANSWERS:

Formula Mass of CuSO₄.5H₂O = 249.6804?molg??

moles of CuSO₄.5H₂O = 0.14 moles

grams of CuSO₄.5H₂O = 798.98 g CuSO₄.5H₂O