question archive You are the webmaster for your firm's website
You are the webmaster for your firm's website
Subject:StatisticsPrice:2.84 Bought7
You are the webmaster for your firm's website. From your records, you know that the probability that a visitor will buy something from your firm is 0.26. In one day, the number of visitors is 750. If the visitors' traffic is more than the expected for the day, what is the probability that at least 10 more than the expected visitors will buy something from the firm?
Purchase A New Answer
Custom new solution created by our subject matter experts
GET A QUOTE
Answer Preview
P(X > 205) = 0.20256
Step-by-step explanation
Here, we need to use normal approximation to binomial
n = 750, P = 0.26,
µ =E(X) = np
=750 (0.26)
=195
Variance (x) =σ2 = npq
where q = 1-p
Thus, σ2 = 750 (0.26)(1-0.26)
=144.3
The standard deviation is sqrt (144.3)
Thus, σ = 12.0125
The expected number of visitors are E(x) = 195. Thus, 10 more than expected will be 195+10
=205
We need to find P(X > 205)
using the formula, z = (x-µ )/σ
we find P(z>(205-195)/ 12.0125)
=P(z>0.8325)
=0.20256
