question archive You are the webmaster for your firm's website
You are the webmaster for your firm's website
Subject:MathPrice:2.87 Bought7
You are the webmaster for your firm's website. From your records, you know that the probability that a visitor will buy something from your firm is 0.27. In one day, the number of visitors is 800. If the visitors’ traffic is more than the expected for the day, what is the probability that at least 5 more than the expected visitors will buy something from the firm?
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Answer:
Given,
Binomial distribution P(X) = nCx*p^x*q^(n-x)
nCx = n!/(n-x)!*x!
sample n = 800
p = 0.27
Expected number of visitors = np = 800*0.27 = 216
P(X >= 216) = P(216) + P(217) + P(218) + ........... + P(800)
= 800C216*0.27^216*0.73^584 + 800C217*0.27^217*0.73^583 + ........... + 800C800*0.27^800*0.73^0
= 0.5134
