A force of 50N is required to keep a 25kg block in motion. What is the coefficient of kinetic friction from this information?

 

The coefficient of kinetic friction is 0.204

Step-by-step explanation

According to the question ,

Given that -

A force of 50N is required to keep a 25kg block in motion -

Let u(k) the kinetic friction of coefficient .

For kinetic friction ,

F = u(k)*N

where N = mg

So , F = u(k) * m * g

put the value in above equation ,

50 = u(k) * 25 * 9.8

u(k) = 50/245

u(k) = 0.204

So the coefficient of kinetic friction is 0.204