question archive It requires 1000 J of work to stretch a spring 3
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It requires 1000 J of work to stretch a spring 3.00 cm. Which of the following is the change in potential energy and the spring constant of the spring?
Answer:
k = 2.22? ×10^6? N/m
change in potential energy = 1000 J
Step-by-step explanation
given that :
length stretched = x = 3 cm = 0.03 m
let spring constant be k
work required = 1000 J
also
work required = ?1/2 ?kx2? = ?1/2?k(0.03)^2?
equating both we have
1000 = ?1?/2k(0.03)^2?
2000 = ?k(0.03)^2?
k = 2.22? ×106^? N/m
change in potential energy = work done in stretching = 1000 J