question archive Introduces a husband and wife with brown eyes who have 0
Introduces a husband and wife with brown eyes who have 0
Subject:BiologyPrice:3.87 Bought7
Introduces a husband and wife with brown eyes who have 0.75 probability of having children with brown eyes, 0.125 probability of having children with blue eyes, and 0.125 probability of having children with green eyes
(a) What is the probability that their first child will have green eyes and the second will not?
(b) What is the probability that exactly one of their two children will have green eyes?
(c) If they have six children, what is the probability that exactly two will have green eyes?
(d) If they have six children, what is the probability that at least one will have green eyes?
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Answer:
a)P(first have green and second not) =0.125*(1-0.125)=0.109375
b)P(Exactly one have)= P(first have and second not)+P(2nd have and 1st not)=0.125*(1-0.125)+(1-0.125)*0.125=0.21875
c)P(X=2)=6C2(0.125)2(1-0.125)4 =0.137386
d)P( at least one)= 1-P(none)=1-P(X=0)=1-(1-0.125)6 =0.551205
