question archive Find the volume of the solid generated by revolving the shaded region about the x-axis
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Find the volume of the solid generated by revolving the shaded region about the x-axis. The volume of the solid is cubic units. (Type an exact answer, using n as needed.)
given equation is 4x+3y =24
=>y=8-(4/3)x
=>y=4*(2-(1/3)x)
for x intercept ,y=0
0=4*(2-(1/3)x)
(1/3)x=2
x=6
volume generated by rotating the given region about x axis by washer method v=∫[0 to 6]π[4*(2-(1/3)x)]2 dx
v=∫[0 to 6]16π[22-2*2*(1/3)x +((1/3)x)2] dx
v=∫[0 to 6]16π[4-(4/3)x +(1/9)x2] dx
v=[0 to 6]16π[4x-(4/3)(1/2)x2 +(1/9)(1/3)x3]
v=[0 to 6]16π[4x -(2/3)x2 +(1/27)x3]
v=16π[4*6 -(2/3)62 +(1/27)63] - 16π[4*0 -(2/3)02 +(1/27)03]
v=16π[4*6 -(2*36/3) +(216/27)]
v=16π[24 -24 +8]
v=128π
volume =128π=402