question archive The mean head circumference of U

The mean head circumference of U

Subject:MathPrice:5.87 Bought7

The mean head circumference of U.S. newborns is 35.0 centimeters (cm) with a standard deviation of 1.3 cm. Assuming a normally distributed population of head circumferences:

A. What percent of newborns have a head circumference greater than 36.0 cm or less than 33.5 cm?

B. Microencephaly in newborns is a condition where an infant’s head is significantly smaller than normal. Some medical researchers consider a newborn to be microcephalic if its head circumference is in the bottom 3% of all newborn head circumferences. Given this definition, what would be the head circumference cutoff (in cm) for classifying a newborn as microcephalic?

C. If a random sample of 26 newborns is selected and their head circumferences are measured, what is the probability that the mean head circumference for this sample is less than 35.1 cm?

pur-new-sol

Purchase A New Answer

Custom new solution created by our subject matter experts

GET A QUOTE

Answer Preview

Solution :

Given that,

mean = \mu = 35.0

standard deviation = \sigma = 15

a ) P (x > 36.0 )

= 1 - P (x < 36.0 )

= 1 - P ( x -  \mu\sigma ) < ( 36.0 - 35.0 / 1.3)

= 1 - P ( z < 1 / 1.3 )

= 1 - P ( z < 0.77)

Using z table

= 1 - 0.7794

= 0.2206

P( x < 33.5 )

P ( x - \mu / \sigma ) < ( 33.5 - 35.0 / 1.3)

P ( z < -1.5 / 1.3 )

P ( z < -1.15)

= 0.1251

= 0.1251 + 0.2206 = 0.3457

Probability = 34.57%

b ) P(Z < z) = 3%

= P(Z < z) = 0.03

= P(Z < -1.88 ) = 0.03

z = -1.88

Using z-score formula,

x = z * \sigma + \mu

x = -1.88 * 1.3 + 35

x = 32.56

c ) n = 26

\mu\bar x = 35

\sigma\bar x = \sigma / √n = 1.3 √26 = 0.2550

P( x < 35.1)

P ( x - \mu / \sigma ) < ( 35.1 - 35.0 / 0.2550)

P ( z < 0.1 / 0.2550 )

P ( z < 0.39)

Probability = 0.6517