question archive A potter's wheel having a radius 0
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A potter's wheel having a radius 0.46 m and a moment of inertia of 13.9 kgm is rotating freely at 53 rev/min. The potter can stop the wheel in 7.5 s by pressing a wet rag against the rim and exerting a radially inward force of 65 N. Find the effective coefficient of kinetic friction between the wheel and the wet rag.
Answer:
let the frictional coefficient is uk
R = 0.46 m
I = 13.9 Kg.m^2
angular speed, w = 53 rev/min
w = 5.55 rad/s
t = 7.5 s
F = 65 N
Now, as torque * time = change in angular momentum
force * radius * time = change in angular momentum
uk * 65 * 0.46 * 7.5 = 13.9 * 5.55
solving for uk
uk = 0.344
the coefficient of kinetic friction is 0.344