A tractor has mass 750.0 kg, while cart A has mass 350.0 kg and cart B has mass 150.0 kg. The driving force acting for a brief period of time accelerates the system from rest and acts for 1 minute.

(a) If this driving force is given by F = 1000t N, find the speed after 5.00 seconds.

(b) What is the horizontal force acting on the connecting cable between the tractor and cart A at this instant?

 

Answer:

a. The speed is 20m/s

b. The horizontal force is 2000 Newtons

Step-by-step explanation

Draw first the figure

From the figure, draw its free body diagram.

Notice from question b that the force from cable of Cart A is required. Therefore in order to expose the axial forces of the cables, you must cut it.

Solve for the force since it states after 5 seconds.

F = 1000t

F = 1000(5)

F = 5000 Newtons

Isolate the forces in each free body diagram(FBD) hence FBD 1, 2 and 3. Note Force = mass x acceleration

You will get 3 equations from perfoming the equation.

From the 3 equations you can get the unknown values by substituting it each equation shown in the picture below.

Once acceleration is solved, you can now find the value of the speed based from the formula of acceleration as shown below from the picture and you can also find the force or tension if you input the value of a = 4m/s^2 to the 1st equation 5000 - TA = 750a.

please use this google drive link to download the answer file.

https://drive.google.com/file/d/1Ea1lHV3nFaIKdpBX0khPHctqc_CQaU96/view?usp=sharing

note: if you have any trouble in viewing/downloading the answer from the given link, please use this below guide to understand the whole process.

https://helpinhomework.org/blog/how-to-obtain-answer-through-google-drive-link