question archive Calculate the heat of combustion of 1
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Calculate the heat of combustion of 1.00 g of each alcohol considering the heat they released after a combustion experiment: Methanol: -22.6 kJ; ethanol: -29.7 kJ; n-propanol: -33.4 kJ. What can you notice from the data?
eat of combustion:
methanol (CH3OH)= -7.23 x 102 kJ/mol = -723 kJ/mol
ethanol(C2H5OH) = -1.37 x 103 kJ/mol = -1370 kJ/mol
n-propanol(C3H7OH) = -2.00 x 103 kJ/mol = -2000 kJ/mol
Based from the data, the heat of combustion increases in magnitude as the number of carbons increases (|?ΔHmethanol??| < |?ΔHethanol??| < |?ΔHn−propanol??|). The reason why heat of combustion increases as the number of carbons increases is there are more carbons available for combustion present in the molecule.
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