question archive C) Reaction with Potassium Permanganate The Baeyer test for unsaturated hydrocarbons involves reaction with a hydrocarbon with alkene (or alkyne) like double bonds
C) Reaction with Potassium Permanganate The Baeyer test for unsaturated hydrocarbons involves reaction with a hydrocarbon with alkene (or alkyne) like double bonds
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C) Reaction with Potassium Permanganate
The Baeyer test for unsaturated hydrocarbons involves reaction with a hydrocarbon with alkene (or alkyne) like double bonds. Even though you can draw double bonds for aromatic hydrocarbons (benzene or toluene), these double bonds do not react like alkene double bonds
Evidence that an alkene-like double bound is present is the rapid dissappearance of the permanganate purple color. Potassium permanganate is a very strong oxidizing agent and can also oxidize other organic compounds, such as alcohols
Add 2-3 drops of 0.8% potassium permanganate solution to about | ml. of hexane, cyclohexene, and toluene added to separate test tubes. Mix the solutions and note the results, including color changes, whether the liquide mixture remains clear, is there change in temperature, etc. Based on your experiments, what types of bonds in hydrocarbons react with potassium permanganate?
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The reaction you propose is called the Baeyer test, after the German organic chemist Adolf von Baeyer, and is used in organic chemistry as a qualitative test to identify the presence of unsaturations caused by double or triple bonds between adjacent carbons. The reaction model and the conclusions of the experiment you mention are explained below
Step-by-step explanation
Baeyer's reagent is an alkaline solution of potassium permanganate, which is a powerful oxidant. Reaction with double (-C = C-) or triple (-C≡C-) bonds in organic material causes the color to fade from purple-pink to brown. Aldehydes and formic acid (and formic acid esters) also test positive.
Therefore, in the experiment that you propose, in cyclohexene and in toluene the appearance of the brown coloration, product of the oxidation of the double bonds, would be observed. While in hexane there would be no color change, since all the bonds are simple
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