question archive 3) Solve the following LP problem: (Show your work and interpret the result) Min z = x1 – x2 S
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3) Solve the following LP problem: (Show your work and interpret the result)
Min z = x1 – x2
S.t. x1 + x2 £ 6
X1 - x2 ³ 0
X2 – x1 ³ 3
X1, x2 ³ 0
X1 = 0 ; X2 = 3 Min Z = -3
But solution is infeasible as it does not satisfy inequality X1 - X2 >= 0 and artificial variable A1 in the base with positive coefficient 3 hence this problem has no feasible solution
2. Solution using graphical method
No feasible region
Please see the attached file for the complete solution