Calculate horizontal impulse needed to come to complete stop given:

• Constant deacceleration of -1.94m/s²
• Over time of 0.33 seconds
• Initial velocity of 3.7m/s

 

The final answer is -266.4 N*s

Step-by-step explanation

Momentum p is a vector value defined as the product of the mass m and velocity v of an object:

p = mv

The change of a body's momentum is called impulse J:

J = Δp = p? - p? = mv? - mv? = mΔv

Delta (Δ) is a symbol that means "change". For example, while p is the instantaneous momentum, Δp depicts the change of momentum that occurred over some period of time.

For this problem

J= (72kg)(0m/s) - (72kg)(3.7m/s)

J=-266.4 kg*m/s or -266.4 N*s