question archive An ammonia/ammonium buffer solution contains 0
An ammonia/ammonium buffer solution contains 0
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An ammonia/ammonium buffer solution contains 0.48 M
M NH
3
NH3 and 0.78 M
MNH
4
+
NH4+. The K
b
KbK_b value of ammonia is 1.8×10
−5
1.8×10−5. Calculate the pH
pH of this buffer.
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For buffers apply Henderson-Hasselbalch equation
pH = pka + log (base/acid)
but we have, Kb
so,
Ka x Kb = Kw
=> Ka = Kw/Kb
= (1.0 X 10-14) / 1.8 X 10-5 = 5.55 X 10-10
pKa = -log Ka
= -log (5.55 X 10-10) = 9.256
pH = 9.256 + log (0.48/0.78) = 9.045
pH =9.045
