question archive Consider the following set of reactions: N2 + 2O2→N2O4 ,ΔH=−8 kJ/mol N2 + O2→2NO ,ΔH=180 kJ/mol The equations given in the problem introduction can be added together to give the following reaction: overall: N2O4→2NO + O2 However, one of them must be reversed, reaction 1: N2 + 2O2→N2O4 What is the enthalpy for reaction 1 reversed? reaction 1 reversed: N2O4→N2 + 2O2 Express your answer numerically in kilojoules per mole
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Consider the following set of reactions:
N2 + 2O2→N2O4 ,ΔH=−8 kJ/mol
N2 + O2→2NO ,ΔH=180 kJ/mol
The equations given in the problem introduction can be added together to give the following reaction:
overall: N2O4→2NO + O2
However, one of them must be reversed, reaction 1: N2 + 2O2→N2O4
What is the enthalpy for reaction 1 reversed?
reaction 1 reversed: N2O4→N2 + 2O2
Express your answer numerically in kilojoules per mole.
What is the enthalpy for reaction 2?
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