At 25
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At 25.0 degrees C , the molar solubility of silver chromate in water is 1.10*10^-12M . Calculate the solubility in grams per liter. Then, How many liters of water are required to dissolve 1.00 g of silver chromate?
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moles per liter = 1.1 x 10^-12 moles per liter
soluility in grams per liter = 331.73 x 1.1 x 10^-12 = 3.65 x 10^-10 gm per liter
for 1 gm silver chromate to dissolve water in liters = ( 1/3.65 x 10^-10) = 2.74 x 10^9 liters
