You must dilute 401 mL with enough water to make 1

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You must dilute 401 mL with enough water to make 1.00 L of solution.

Step 1. Calculate the of the stock solution.

Moles of Ba(OH)? = ##"51.24 g Ba(OH)"_2 × ("1 mol Ba(OH)"_2)/("171.34 g Ba(OH)"_2) = "0.299 05 mol Ba(OH)"_2##

Molarity = ##"moles"/"litres" = "0.299 05 mol"/"1.20 L"## = 0.2492 mol/L

Step 2. Calculate the volume of stock solution that is needed.

See

##c_1V_1 = c_2V_2##

##c_1## = 0.2492 mol/L; ##V_1## = ? ##c_2## = 0.100 mol/L; ##V_2## = 1.00 L

##V_1 = V_2 × c_2/c_1## = ##"1.00 L" × "0.100 mol/L"/"0.2492 mol/L"## = 0.401 L = 401 mL

So, to make your solution, you would dilute 401 mL of stock solution with enough water to make 1.00 L.